x+25=2x^2

Solution for x+25=2x^2 equation:

x+25=2x^2

We move all terms to the left:

x+25-(2x^2)=0

determiningTheFunctionDomain
-2x^2+x+25=0

a = -2; b = 1; c = +25;
Δ = b2-4ac
Δ = 12-4·(-2)·25
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{201}}{2*-2}=\frac{-1-\sqrt{201}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{201}}{2*-2}=\frac{-1+\sqrt{201}}{-4}
$